Вопрос

How do I recognize in a servlet whether the request sent using HTML form has enctype multipart/form-data or the default application/x-www-form-urlencoded?

Alternatively: is there any other way to recognize which form was used? request.getParameter("some_param") works only with default encoding.

Это было полезно?

Решение

I'm using Apache Commons FileUpload for multipart, but wasn't sure how to switch between handling multipart and default forms

Use Apache Commons FileUpload's own ServletFileUpload#isMultipartContent() to check it.

if (ServletFileUpload.isMultipartContent(request)) {
    // Parse with FileUpload.
}
else {
    // Use normal getParameter().
}

See also:

Другие советы

You can identify using Content-Type: header

if(HttpServletRequest.getContentType().contains("form-data")){
   //handle multipart data
 ....
} else if(HttpServletRequest.getContentType().contains("x-www-form-urlencoded")){
   //handle from data
 ....
}

If the web container supports Servlet 3.0, the use HttpServletRequest.getParts() API.

if(request.getParts() !=null){
  //handle multipart
} else {
  //handle form data
}
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