How do I implement Hash#all? for multidimensional hashes?
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15-03-2021 - |
Вопрос
Given that I have these hashes:
h1 = {"a" => { "b" => 1, "c" => {"d" => 2, "e" => 3} } }
h2 = {"a" => { "b" => 1, "c" => nil } }
And I want these results:
h1.multi_all? # true
h2.multi_all? # false
How would I implement the multi_all method?
Решение
class Hash
def multi_all? &block
all? do |key, value|
if value.is_a?(Hash)
value.multi_all?(&block)
elsif block == nil
value
else
block[key, value]
end
end
end
end
Другие советы
class Hash
def values_r # recursive values
self.values.map do |x|
x.is_a?(Hash) ? x.values_r : x
end
end
end
h1.values_r.flatten.all?
PS: do you know that all?
method also accepts a block?
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