Pergunta

This is in the context of Web Services (client end). I need to interface with a back-end system (Java) and it is a requirement to transmit some control characters in the  and  range.

I'm well aware that XML 1.0 doesn't support this, but am interested to know if the .NET 4 platform or .NET 4.5 web services framework support conversations in XML 1.1.

Foi útil?

Solução

No, it doesn't look like XmlReader (the core of much of the XML support in .NET) supports 1.1:

using System;
using System.IO;
using System.Xml;

class Program
{
    static void Main(string[] args)
    {
        string xml = "<?xml version=\"1.1\" ?><tag>&#x1</tag>";
        var reader = XmlReader.Create(new StringReader(xml));
        while (reader.Read());
    }
}

Output:

Unhandled Exception: System.Xml.XmlException: Version number '1.1' is invalid.
Line 1, position 16.

I've looked at XmlReaderSettings to see if anything there would help, but I don't think it does. Basically I think you're stuck for the moment :(

EDIT: Reading around XML 1.1 a bit, it looks like it's not widely deployed or recommended, so I'm not particularly surprised that it's not supported in .NET 4.5. My guess is that it never will be, given that it's not a particularly new recommendation. The most recent version is the 2nd edition which dates back to 2006. If it's not supported 7 years later, I suspect there'd have to be some significant event to make it worth supporting in the future.

Outras dicas

I am sure this is not the best option but if you download IKVM you can use java classes in your .Net code after referencing a few assemblies (really .Net code :) )

var fXmlFile = new java.io.File(xmlfile);

var dbFactory = javax.xml.parsers.DocumentBuilderFactory.newInstance();
var dBuilder = dbFactory.newDocumentBuilder();

var doc = dBuilder.parse(fXmlFile);
var nList = doc.getElementsByTagName("controlcharacters");

var chars = nList.item(0).getTextContent().ToCharArray();

XML File:

<?xml version="1.1" ?>
<root>
    <controlcharacters>&#14;&#15;</controlcharacters>
</root>
Licenciado em: CC-BY-SA com atribuição
Não afiliado a StackOverflow
scroll top