Domanda

Ho creato un menu in Umbraco utilizzando XSLT. Il menu sta usando i soliti elementi ul e li e sto mostrando solo il primo livello del menu. L'obiettivo è quello di creare un menu che si espande per mostrare il sottomenu quando clicco un nodo padre (nel livello superiore).

Sto dopo l'XSLT avrei bisogno di esporre il sottomenu quando si fa clic.

Credo che avrei avuto bisogno di fare uso di antenato-or-self per rilevare il menu menu e padre corrente e di visualizzarli e anche la variabile $ currentPage.

Ho il seguente XSLT:

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet 
  version="1.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
    xmlns:msxml="urn:schemas-microsoft-com:xslt" 
    xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:urlLib="urn:urlLib" 
    exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets tagsLib urlLib ">

<xsl:output method="xml" omit-xml-declaration="yes"/>

<xsl:param name="currentPage"/>

<xsl:template match="/">
    <div id="kb-categories"> 
        <h3>Categories</h3>
        <xsl:call-template name="drawNodes">  
            <xsl:with-param name="parent" select="$currentPage/ancestor-or-self::node [@level=1]"/>  
        </xsl:call-template>
    </div>
</xsl:template>

<xsl:template name="drawNodes">
    <xsl:param name="parent"/> 
    <xsl:if test="(umbraco.library:IsProtected($parent/@id, $parent/@path) = 0 or (umbraco.library:IsProtected($parent/@id, $parent/@path) = 1)) and $parent/@level = 1">           
        <ul class="kb-menuLevel1" >     
        <xsl:for-each select="$parent/node [string(./data [@alias='showInMenu']) = 1]"> 
            <li>  
                <a href="/kb{umbraco.library:NiceUrl(@id)}">
                    <xsl:value-of select="@nodeName"/>
                </a>                
                <xsl:variable name="level" select="@level" />
                <xsl:if test="(count(./node [string(./data [@alias='showInMenu']) = '1']) &gt; 0)">   
                    <xsl:call-template name="drawNodes">    
                        <xsl:with-param name="parent" select="."/>    
                    </xsl:call-template>  
                </xsl:if> 
            </li> 
        </xsl:for-each>
        </ul>
    </xsl:if>
    <xsl:if test="(umbraco.library:IsProtected($parent/@id, $parent/@path) = 0 or (umbraco.library:IsProtected($parent/@id, $parent/@path) = 1)) and $parent/@level &gt; 1">    
        <ul class="kb-menuLevel{@level}" style="display: none;">            
        <xsl:for-each select="$parent/node [string(./data [@alias='showInMenu']) = 1]"> 
            <li>  
                <a href="/kb{umbraco.library:NiceUrl(@id)}">
                    <xsl:value-of select="@nodeName"/>
                </a>                
                <xsl:variable name="level" select="@level" />
                <xsl:if test="(count(./node [string(./data [@alias='showInMenu']) = '1']) &gt; 0)">   
                    <xsl:call-template name="drawNodes">    
                        <xsl:with-param name="parent" select="."/>    
                    </xsl:call-template>  
                </xsl:if> 
            </li>
        </xsl:for-each>
        </ul>
    </xsl:if>

</xsl:template>

</xsl:stylesheet>

ho il sospetto che questo potrebbe essere migliorata utilizzando apply-templates, ma io non sono ancora al passo con che (questo essere solo il secondo giorno del mio apprendimento XSLT).

Il mio menù:

  • Voce di menu 1
  • Voce di menu 2
  • Voce di menu 3
  • Voce di menu 4

quando clicco su voce di menu 2 mi saranno adottate per la pagina per la Voce 2 e sarà anche visualizzato il sottomenu:

  • Voce di menu 1
  • Menu Opzione 2
    - Voce di menu 2.1
    - Voce di menu 2.2
  • Voce di menu 3
  • Voce di menu 4

e così via il menu nidificate.

Ecco alcuni XML di esempio per quanto sopra.

<root>  
    <node id="1" nodeTypeAlias="kbHomepage" nodeName="Home" level="1">
        <data alias="introduction">
            <![CDATA[<p>Welcome</p>]]>
        </data>
        <node id="2" nodeTypeAlias="guide" nodeName="Menu Item 1" level="2">
            <data alias="bodyText">
                <![CDATA[<p>This is some text</p>]]>
            </data>
            <data alias="showInMenu">1</data>
            <data alias="menuName">Menu Item 1</data>
        </node>     
        <node id="3" nodeTypeAlias="guide" nodeName="Menu Item 2" level="2">
            <data alias="bodyText">
                <![CDATA[<p>This is some text</p>]]>
            </data>
            <data alias="showInMenu">1</data>
            <data alias="menuName">Menu Item 2</data>
            <node id="4" nodeTypeAlias="guide" nodeName="Menu Item 2.1" level="3">
                <data alias="bodyText">
                    <![CDATA[<p>Some Text</p>]]>
                </data>
                <data alias="showInMenu">1</data>
                <data alias="menuName">Menu Item 2.1</data>
            </node>
            <node id="5" nodeTypeAlias="guide" nodeName="Menu Item 2.2" level="3">
                <data alias="bodyText">
                    <![CDATA[<p>Some Text</p>]]>
                </data>
                <data alias="showInMenu">1</data>
                <data alias="menuName">Menu Item 2.2</data>
                <node id="6" nodeTypeAlias="guide" nodeName="Item 2.2.1 Guide" level="4">
                    <data alias="bodyText">
                        <![CDATA[<p>Some Text</p>]]>
                    </data>
                    <data alias="showInMenu">0</data>
                    <data alias="menuName"></data>
                </node>
            </node>
        </node>     
        <node id="8" nodeTypeAlias="guide" nodeName="Menu Item 3" level="2">
            <data alias="bodyText">
                <![CDATA[<p>This is some text</p>]]>
            </data>
            <data alias="showInMenu">1</data>
            <data alias="menuName">Menu Item 3</data>
        </node>     
        <node id="9" nodeTypeAlias="guide" nodeName="Menu Item 4" level="2">
            <data alias="bodyText">
                <![CDATA[<p>This is some text</p>]]>
            </data>
            <data alias="showInMenu">1</data>
            <data alias="menuName">Menu Item 4</data>
        </node>     
    </node>
    <node id="7" nodeTypeAlias="someAlias" nodeName="Some Other Page" level="1">
        <data alias="bodyText">
            <![CDATA[<p>This is some text</p>]]>
        </data>         
    </node>     
</root>

modifica: le seguenti quasi fa quello che mi serve:

<xsl:variable name="visibleChidren" select="node[data[@alias='showInMenu'] = 1 and (@level = 2 or descendant-or-self::*[generate-id($currentPage) = generate-id(.)] or preceding-sibling::*[generate-id($currentPage) = generate-id(.)] or following-sibling::*[generate-id($currentPage) = generate-id(.)])]" />

Ho solo bisogno di includere anche i figli diretti dalla pagina corrente.

È stato utile?

Soluzione 2

ho capito cosa devo fare quello che voglio. Il tasto di linea essere:

<xsl:variable name="visibleChidren" select="node[data[@alias='showInMenu'] = 1 and (@level = 2 or descendant-or-self::*[generate-id($currentPage) = generate-id(.)] or preceding-sibling::*[generate-id($currentPage) = generate-id(.)] or following-sibling::*[generate-id($currentPage) = generate-id(.)] or parent::*[generate-id($currentPage) = generate-id(.)])]" />

Dalla intera XSLT:

<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:urlLib="urn:urlLib"
  exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets tagsLib urlLib ">

  <xsl:output method="xml" omit-xml-declaration="yes"/>

  <xsl:param name="currentPage"/>
  <xsl:variable name="currentLevel" select="$currentPage/@level" />

  <xsl:template match="/">
    <div id="kb-categories">
      <h3>Categories</h3>
      <xsl:apply-templates mode="list" select="$currentPage/ancestor-or-self::node [@nodeTypeAlias = 'kbHomepage']" />
    </div>
  </xsl:template>

  <!-- matches anything with <node> children and makes a list out of them -->
  <xsl:template match="node" mode="list">
    <!-- select only sub-nodes that have 'showInMenu' = 1 -->
    <xsl:variable name="visibleChidren" select="node[data[@alias='showInMenu'] = 1 and (@level = 2 or descendant-or-self::*[generate-id($currentPage) = generate-id(.)] or preceding-sibling::*[generate-id($currentPage) = generate-id(.)] or following-sibling::*[generate-id($currentPage) = generate-id(.)] or parent::*[generate-id($currentPage) = generate-id(.)])]" />
    <xsl:if test="$visibleChidren">
      <ul>
        <xsl:apply-templates mode="item" select="$visibleChidren" />
      </ul>
    </xsl:if>
  </xsl:template>

  <xsl:template match="node" mode="item">
      <li>
        <a href="/kb{umbraco.library:NiceUrl(@id)}">
          <xsl:value-of select="@nodeName"/>
        </a>
        <xsl:apply-templates mode="list" select="." />
      </li>
  </xsl:template>

</xsl:stylesheet>

Altri suggerimenti

ho provato (con il mio molto limitata conoscenza di Umbraco) per ripulire il codice un po 'e rimuovere la ridondanza. Sembra come se avrebbe funzionato con l'XML di esempio che hai fornito, ma non posso davvero testare contro Umbraco.

<!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:msxml="urn:schemas-microsoft-com:xslt"
  xmlns:umbraco.library="urn:umbraco.library" xmlns:Exslt.ExsltCommon="urn:Exslt.ExsltCommon" xmlns:Exslt.ExsltDatesAndTimes="urn:Exslt.ExsltDatesAndTimes" xmlns:Exslt.ExsltMath="urn:Exslt.ExsltMath" xmlns:Exslt.ExsltRegularExpressions="urn:Exslt.ExsltRegularExpressions" xmlns:Exslt.ExsltStrings="urn:Exslt.ExsltStrings" xmlns:Exslt.ExsltSets="urn:Exslt.ExsltSets" xmlns:tagsLib="urn:tagsLib" xmlns:urlLib="urn:urlLib"
  exclude-result-prefixes="msxml umbraco.library Exslt.ExsltCommon Exslt.ExsltDatesAndTimes Exslt.ExsltMath Exslt.ExsltRegularExpressions Exslt.ExsltStrings Exslt.ExsltSets tagsLib urlLib ">

  <xsl:output method="xml" omit-xml-declaration="yes" encoding="utf-8" />

  <xsl:param name="currentPage" />

  <xsl:template match="/">
    <div id="kb-categories">
      <h3>Categories</h3>
      <xsl:apply-templates mode="list" select="/root/node[@nodeTypeAlias='kbHomepage']" />
    </div>
  </xsl:template>

  <!-- matches anything with <node> children and creates an <ul> -->
  <xsl:template match="*[node]" mode="list">
    <!-- prepare a list of all visible children -->
    <xsl:variable name="visibleChidren" select="node[
      data[@alias='showInMenu'] = 1
      and (
        not(umbraco.library:IsProtected(@id, @path)) 
        or umbraco.library:IsLoggedOn() 
      )
    ]" />
    <!-- prepare a CSS class for the "selected path" -->
    <xsl:variable name="display">
      <xsl:if test=".//node[generate-id() = generate-id($currentPage)]">
        <xsl:text>visible</xsl:text>
      </xsl:if>
    </xsl:variable>
    <xsl:if test="$visibleChidren">
      <ul class="menu kb-menuLevel{$visibleChidren[1]/@level} {$display}">
        <xsl:apply-templates mode="item" select="$visibleChidren" />
      </ul>
    </xsl:if>
  </xsl:template>

  <!-- matches <node> elements and turns them into list items -->
  <xsl:template match="node" mode="item">
    <li>
      <xsl:if test="generate-id() = generate-id($currentPage)">
        <xsl:attribute name="class">selected</xsl:attribute>
      </xsl:if>
      <a href="/kb{{umbraco.library:NiceUrl(@id)}}">
        <xsl:value-of select="@nodeName" />
      </a>
      <!-- if there are any child nodes, render them -->
      <xsl:if test="node">
        <xsl:apply-templates mode="list" select="." />
      </xsl:if>
    </li>
  </xsl:template>

</xsl:stylesheet>

offre le seguenti. Si noti che ho sfuggito il modello di valore di attributo in <a href... - rimuovere il doppio curlies sopra per permettere loro di nuovo:

<div id="kb-categories">
  <h3>Categories</h3>
  <ul class="menu kb-menuLevel2 visible">
    <li>
      <a href="/kb{umbraco.library:NiceUrl(@id)}">Menu Item 1</a>
    </li>
    <li>
      <a href="/kb{umbraco.library:NiceUrl(@id)}">Menu Item 2</a>
      <ul class="menu kb-menuLevel3 visible">
        <li class="selected">
          <a href="/kb{umbraco.library:NiceUrl(@id)}">Menu Item 2.1</a>
        </li>
        <li>
          <a href="/kb{umbraco.library:NiceUrl(@id)}">Menu Item 2.2</a>
        </li>
      </ul>
    </li>
    <li>
      <a href="/kb{umbraco.library:NiceUrl(@id)}">Menu Item 3</a>
    </li>
    <li>
      <a href="/kb{umbraco.library:NiceUrl(@id)}">Menu Item 4</a>
    </li>
  </ul>
</div>

Ora si potrebbe fare in CSS:

ul.menu {
  display: hidden;
}
ul.menu.visible {
  display: block;
}
ul.menu li.selected {
  font-weight: bold;
}

Fa che ti aiutano a?

Oppure si potrebbe risolvere un sacco di hacker circa in XSLT e utilizzare il seguente pacchetto di navigazione da our.umbraco.org

Questa penso fa tutto il necessario e non c'è bisogno di ottenere il vostro mani sporche nel torbido mondo di XSLT.

http://our.umbraco.org/projects/cogworks-- -Flessibile-navigazione

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