If I understand your situation correctly, you can just reshape
it.
In [132]: p = np.array("p_x1y1z1 p_x2y1z1 p_x3y1z1 p_x4y1z1 p_x1y2z1 p_x2y2z1 p_x3y2z1 p_x4y2z1".split())
In [133]: p
Out[133]:
array(['p_x1y1z1', 'p_x2y1z1', 'p_x3y1z1', 'p_x4y1z1', 'p_x1y2z1', 'p_x2y2z1', 'p_x3y2z1', 'p_x4y2z1'],
dtype='|S8')
It appears to me that your array is ordered in what numpy calls 'F'
ordering:
In [168]: p.reshape(4, 2, order='F')
Out[168]:
array([['p_x1y1z1', 'p_x1y2z1'],
['p_x2y1z1', 'p_x2y2z1'],
['p_x3y1z1', 'p_x3y2z1'],
['p_x4y1z1', 'p_x4y2z1']],
dtype='|S8')
If you have z
variance, too, simply reshape to three dimensions:
In [169]: q
Out[169]:
array(['p_x1y1z1', 'p_x2y1z1', 'p_x3y1z1', 'p_x4y1z1', 'p_x1y2z1',
'p_x2y2z1', 'p_x3y2z1', 'p_x4y2z1', 'p_x1y1z2', 'p_x2y1z2',
'p_x3y1z2', 'p_x4y1z2', 'p_x1y2z2', 'p_x2y2z2', 'p_x3y2z2',
'p_x4y2z2', 'p_x1y1z3', 'p_x2y1z3', 'p_x3y1z3', 'p_x4y1z3',
'p_x1y2z3', 'p_x2y2z3', 'p_x3y2z3', 'p_x4y2z3'],
dtype='|S8')
In [170]: q.reshape(4,2,3,order='F')
Out[170]:
array([[['p_x1y1z1', 'p_x1y1z2', 'p_x1y1z3'],
['p_x1y2z1', 'p_x1y2z2', 'p_x1y2z3']],
[['p_x2y1z1', 'p_x2y1z2', 'p_x2y1z3'],
['p_x2y2z1', 'p_x2y2z2', 'p_x2y2z3']],
[['p_x3y1z1', 'p_x3y1z2', 'p_x3y1z3'],
['p_x3y2z1', 'p_x3y2z2', 'p_x3y2z3']],
[['p_x4y1z1', 'p_x4y1z2', 'p_x4y1z3'],
['p_x4y2z1', 'p_x4y2z2', 'p_x4y2z3']]],
dtype='|S8')
This assumes x,y,z
should map to i+1,j+1,k+1
, as seen here:
In [175]: r = q.reshape(4,2,3,order='F')
In [176]: r[0] #all x==1
Out[176]:
array([['p_x1y1z1', 'p_x1y1z2', 'p_x1y1z3'],
['p_x1y2z1', 'p_x1y2z2', 'p_x1y2z3']],
dtype='|S8')
In [177]: r[:,0] # all y==1
Out[177]:
array([['p_x1y1z1', 'p_x1y1z2', 'p_x1y1z3'],
['p_x2y1z1', 'p_x2y1z2', 'p_x2y1z3'],
['p_x3y1z1', 'p_x3y1z2', 'p_x3y1z3'],
['p_x4y1z1', 'p_x4y1z2', 'p_x4y1z3']],
dtype='|S8')
In [178]: r[:,:,0] #all z==1
Out[178]:
array([['p_x1y1z1', 'p_x1y2z1'],
['p_x2y1z1', 'p_x2y2z1'],
['p_x3y1z1', 'p_x3y2z1'],
['p_x4y1z1', 'p_x4y2z1']],
dtype='|S8')