Break-continue without auxiliary boolean variable?

Question

In Java, I have such code:

boolean contains;
for (int i = 0; i < n; i++) {
    // get the current matrix value
    t = A[i][j];

    // check if it has been already considered
    contains = false;
    for (int z = 0; z < l; z++) {
        if (arrays[z].contains(t)) {
            contains = true; break;
        }
    }
    if (contains) continue;
    ...
}

Is it possible to use label then jump out of the inner loop and do continue without a boolean variable contains?

I need to do break-continue and not break from all loops.

Answer 1

outerLoop:
for (int i = 0; i < n; i++) {
    // get the current matrix value
    t = A[[i]][j];
    // check if it has been already considered
    for (int z = 0; z < l; z++) {
        if (arrays[z].contains(t)) {
            continue outerLoop;
        }
    }
}

Oracle's documentation on labelled branching

Answer 2

Using labes leads to spaghetti code making your code less readable.

You could extract the inner for-loop in its own method returning a boolean:

private boolean contains(/* params */) {
    for (int z = 0; z < l; z++) {
        if (arrays[z].contains(t)) {
            return true;
        }
    }
}

and use it in the outer for-loop

for (int i = 0; i < n; i++) {
    // get the current matrix value
    t = A[[i]][j];

    // check if it has been already considered
    if (contains(/*params*/)) 
        continue;
    ...
}