getting second to last record per group in SQL

Question

I know how to get the last record of a group but I also need to get the second to last record. How can I do this? here is my code for getting the last record.

select job qjob, max(id) qid from sqbclog group by job

Answer 1

SELECT * 
FROM (
select job AS qjob
      , id AS qid
      ,ROW_NUMBER() OVER (PARTITION BY JOB ORDER BY ID DESC) AS RN
from sqbclog
)Sub
WHERE rn <= 2

This query will return last two records but if you only need the 2nd last record then in where clause use where en = 2 else leave it as it is.

Answer 2

This should do it !

select * 
    from sqbclog 
    where id not in (
        select top (
            (select count(*) from sqbclog ) - 2
        ) id 
        from sqbclog 
    )

Answer 3

If I've understood your original query correctly, and it does in fact give you the last row, then TOP 2 should give you the last 2 rows:

SELECT TOP 2 job qjob, max(id) qid from sqbclog group by job

Answer 4

select job qjob, max(id) -1 qid 
from sqbclog
group by job