我想模拟整个点击不仅仅是

document.getElementsByClassName()[0].click();
.

我该怎么做?搜索结果似乎是关于处理此类事件,而不是触发它们。

有帮助吗?

解决方案

发送鼠标事件。如:

//--- Get the first link that has "stackoverflow" in its URL.
var targetNode = document.querySelector ("a[href*='stackoverflow']");
if (targetNode) {
    //--- Simulate a natural mouse-click sequence.
    triggerMouseEvent (targetNode, "mouseover");
    triggerMouseEvent (targetNode, "mousedown");
    triggerMouseEvent (targetNode, "mouseup");
    triggerMouseEvent (targetNode, "click");
}
else
    console.log ("*** Target node not found!");

function triggerMouseEvent (node, eventType) {
    var clickEvent = document.createEvent ('MouseEvents');
    clickEvent.initEvent (eventType, true, true);
    node.dispatchEvent (clickEvent);
}
.


如果网页在静态加载的情况下。如果网页是ajax驱动的,请使用一种:


小号:
问题代码有一个错误。您需要将类名称传递给该函数。如:

document.getElementsByClassName ("SomeClassName")[0].click();
.

其他提示

我改进了 Brock的代码它在它对我的预期工作后一点。

定义:

function simulateMouseClick(targetNode) {
    function triggerMouseEvent(targetNode, eventType) {
        var clickEvent = document.createEvent('MouseEvents');
        clickEvent.initEvent(eventType, true, true);
        targetNode.dispatchEvent(clickEvent);
    }
    ["mouseover", "mousedown", "mouseup", "click"].forEach(function(eventType) { 
        triggerMouseEvent(targetNode, eventType);
    });
}
.

调用示例:

simulateMouseClick(document);

simulateMouseClick(document.querySelector("a[href*='stackoverflow']"));
.

位优化

function fireMouseEvents( query, eventNames ){
    var element = document.querySelector(query);
    if(element && eventNames && eventNames.length){
        for(var index in eventNames){
            var eventName = eventNames[index];
            if(element.fireEvent ){
                element.fireEvent( 'on' + eventName );     
            } else {   
                var eventObject = document.createEvent( 'MouseEvents' );
                eventObject.initEvent( eventName, true, false );
                element.dispatchEvent(eventObject);
            }
        }
    }
}
.

你会像这个一样闪光

fireMouseEvents("a[href*='stackoverflow']",['mouseover','mousedown','mouseup','click']);
.

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