SQL需要从列返回范围
-
22-10-2019 - |
题
我有一个表格的列,上面有一个名为ID的整数列,其值可能具有差距(例如1,2,3,4,7,8,10,14,15,16,20)
我想找到一个查询,在上面的示例中,它会导致这样做:
1-4 7-8 10 14-16 20
= update =
多亏了下面的代码(似乎在SQL Server中运行良好),我觉得我非常接近在MS-Access中使用它,这是目标。尽管在我的陈述中,我仍然遇到语法错误,但我无法弄清楚...
从(从
SELECT islands.PORTID, CSTR(islands.PORTID ) as val
FROM MYTABLE islands
WHERE NOT EXISTS (SELECT * FROM MYTABLE t2 WHERE t2.PORTID = islands.PORTID - 1)
AND NOT EXISTS (SELECT * FROM MYTABLE t2 WHERE t2.PORTID = islands.PORTID + 1)
UNION
SELECT
rngStart.PORTID
,CSTR(rngStart.PORTID ) + '-'
+ CSTR(MIN(rngEnd.PORTID)) as val
FROM MYTABLE rngStart
INNER JOIN MYTABLE checkNext ON checkNext.PORTID = rngStart.PORTID + 1
INNER JOIN
(
SELECT PORTID
FROM MYTABLE tblRangeEnd
WHERE NOT EXISTS (SELECT * FROM MYTABLE t2 WHERE t2.PORTID = tblRangeEnd.PORTID + 1)
) rngEnd on rngEnd.PORTID > rngStart.PORTID
WHERE NOT EXISTS (SELECT * FROM MYTABLE t2 WHERE t2.PORTID = rngStart.PORTID - 1)
GROUP BY rngStart.PORTID
)作为portid asc的tbl订单
解决方案
SELECT val FROM
(
-- Get the islands
SELECT islands.ID, CAST(islands.ID as varchar(10)) as val
FROM @t1 islands
WHERE NOT EXISTS (SELECT * FROM @t1 t2 WHERE t2.ID = islands.ID - 1)
AND NOT EXISTS (SELECT * FROM @t1 t2 WHERE t2.ID = islands.ID + 1)
UNION
-- Get the ranges
SELECT
rngStart.ID
,CAST(rngStart.ID as varchar(10)) + '-'
+ CAST(MIN(rngEnd.ID) as varchar(10)) as val
FROM @t1 rngStart
INNER JOIN @t1 checkNext ON checkNext.ID = rngStart.ID + 1
INNER JOIN
(
SELECT ID
FROM @t1 tblRangeEnd
WHERE NOT EXISTS (SELECT * FROM @t1 t2 WHERE t2.ID = tblRangeEnd.ID + 1)
) rngEnd on rngEnd.ID > rngStart.ID
WHERE NOT EXISTS (SELECT * FROM @t1 t2 WHERE t2.ID = rngStart.ID - 1)
GROUP BY rngStart.ID
) as tbl
ORDER BY ID ASC
我使用了一个名为 @t1的表变量,但只需将其替换为您的表名。
这里 它正在行动。
编辑
为了使这项工作在访问中进行,您将不得不更改连接。尝试这个:
SELECT val FROM
(
SELECT islands.PORTID, CSTR(islands.PORTID) as val
FROM MYTABLE islands
WHERE NOT EXISTS
(SELECT * FROM MYTABLE t2 WHERE t2.PORTID = islands.PORTID - 1)
AND NOT EXISTS
(SELECT * FROM MYTABLE t2 WHERE t2.PORTID = islands.PORTID + 1)
UNION
SELECT
rngStart.PORTID
,CSTR(rngStart.PORTID) + '-' + CSTR(MIN(endPORTID)) as val
FROM MYTABLE rngStart
INNER JOIN
(
SELECT checkNext.PORTID as nextPORTID, rngEnd.PORTID as endPORTID
FROM MYTABLE checkNext
INNER JOIN
(
SELECT rngEnd.PORTID
FROM MYTABLE rngEnd
WHERE NOT EXISTS
(SELECT * FROM MYTABLE t2 WHERE t2.PORTID = rngEnd.PORTID + 1)
) AS rngEnd on rngEnd.PORTID > checkNext.PORTID - 1
) AS checkNext ON checkNext.nextPORTID = rngStart.PORTID + 1
WHERE NOT EXISTS
(SELECT * FROM MYTABLE t2 WHERE t2.PORTID = rngStart.PORTID - 1)
GROUP BY rngStart.PORTID
) as tbl
ORDER BY PORTID ASC
其他提示
create table #sequence (id int not null primary KEY)
insert into #sequence(id)
select 1
union all select 2
union all select 3
union all select 4
union all select 7
union all select 8
union all select 10
union all select 14
union all select 15
union all select 16
union all select 20
--Find Contig ranges
select l.id as start,
(
select min(a.id) as id
from #sequence as a
left outer join #sequence as b on a.id = b.id - 1
where b.id is null
and a.id >= l.id
) AS fend
from #sequence as l
left outer join #sequence as r on r.id = l.id - 1
where r.id is null;
--Find missing values in sequence
select l.id + 1 as start, min(fr.id) - 1 as stop
from #sequence as l
left outer join #sequence as r on l.id = r.id - 1
left outer join #sequence as fr on l.id < fr.id
where r.id is null and fr.id is not null
group by l.id, r.id;
drop table #sequence
这将为您提供范围之间的范围和差距,因此您可以看到所拥有的或需要的东西。提供的示例数据
如果您访问功能,这将起作用 row_number()
.
with C as
(
select ID,
ID - row_number() over(order by ID) as grp
from YourTable
)
select min(ID) as MinID,
max(ID) as MaxID
from C
group by grp
或带有子查询而不是常见的表表达式。
select min(ID) as MinID,
max(ID) as MaxID
from (select ID,
ID - row_number() over(order by ID) as grp
from YourTable) as C
group by grp
结果:
MinID MaxID
----------- -----------
1 4
7 8
10 10
14 16
20 20
在SQL Server上尝试 http://data.stackexchange.com/stackoverflow/q/119411/
另一个尝试:
SELECT
MIN(i), MAX(i)
FROM (
select
i - (SELECT COUNT(*) FROM tbl t WHERE t.i < tbl.i) g,
i
from tbl
) t
GROUP BY g
当然,这会很慢,但是我看不到其他访问中编号行的方法。
不隶属于 StackOverflow