将所有XML节点导入到SQL Server中
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20-09-2019 - |
题
我已经将XML文档导入到SQL Server中,现在我正在尝试将各个部分导入不同的表。当我使用以下查询时,它仅返回一排hotel_facities,我需要用hotel_ref返回所有hotel_facities。
DECLARE @Details xml
SET @Details = '<hotels>
<hotel>
<hotel_ref>105</hotel_ref>
<hotel_facilities>
<id>2</id>
<name>Disabled Facilities</name>
<id>4</id>
<name>24 Hour Reception</name>
<id>12</id>
<name>Restaurant</name>
</hotel_facilities>
</hotel>
</hotels>'
SELECT tab.col.value('../hotel_ref[1]','varchar(100)') AS 'hotel_ref',
tab.col.value('./id[1]','varchar(100)') AS 'HotelFacilityID',
tab.col.value('./name[1]','varchar(100)') AS 'HotelFacilityName'
FROM @Details.nodes('//hotels/hotel/hotel_facilities') AS tab(col)
解决方案
我同意MARC_S XML没有良好的模式。
我最接近的是:
SELECT tab.col.value('./hotel_ref[1]','varchar(100)') AS 'hotel_ref',
fac.value('(.)[1]','varchar(100)') AS 'HotelFacilityID',
ROWID=IDENTITY(int,1,1)
into #facilitiesid
FROM @Details.nodes('/hotels/hotel') AS tab(col)
cross apply col.nodes('.//id') a(fac)
SELECT tab.col.value('../hotel_ref[1]','varchar(100)') AS 'hotel_ref',
fac.value('(.)[1]','varchar(100)') AS 'HotelFacilityName',
ROWID=IDENTITY(int,1,1)
into #facilitiesnames
FROM @Details.nodes('//hotels/hotel/hotel_facilities') AS tab(col)
cross apply col.nodes('.//name') a(fac)
select i.hotel_ref, HotelFacilityID, HotelFacilityName
from #facilitiesid i
inner join #facilitiesnames n
on i.rowid = n.rowid
其他提示
您的XML结构有些有趣 - <hotel_facilities>
不包含适当的“子实体”,您可以列举这……
如果您的设施将被包裹在 <facility>....</facility>
元素,您可以轻松地列举这一点。
<hotel_facilities>
<facility>
<id>2</id>
<name>Disabled Facilities</name>
</facility>
<facility>
<id>4</id>
<name>24 Hour Reception</name>
</facility>
<facility>
<id>12</id>
<name>Restaurant</name>
</facility>
</hotel_facilities>
但是,有了您当前的设置,我认为您很难找到一个好的解决方案。
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