显示同一气泡中用户的连续聊天
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26-12-2019 - |
题
我正在开发聊天应用程序..这就是我到目前为止所做的。
现在我想要的是这样的:
拜托,我被困住了,不知道如何处理这个用户界面。即,如果用户查看再次查看聊天,则如果来自用户的味精是连续的,则在与第二张图像中的同一气泡中显示它们。这个聊天的东西都是本地的,没有使用任何服务或服务器。我正在给出我的代码。
消息活动.java
public class MessageActivity extends ListActivity {
/** Called when the activity is first created. */
ArrayList<Message> messages;
AwesomeAdapter adapter;
EditText text;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
text = (EditText) this.findViewById(R.id.text);
this.setTitle("Harish");
messages = new ArrayList<Message>();
adapter = new AwesomeAdapter(this, messages);
setListAdapter(adapter);
}
public void sendMessage(View v)
{
String newMessage = text.getText().toString().trim();
//String msg="\nTesting";
if(newMessage.length() > 0)
{
text.setText("");
//addNewMessage(new Message(newMessage+msg, true));
addNewMessage(new Message(newMessage, true));
}
}
public void sendMessage2(View v)
{
String newMessage = text.getText().toString().trim();
if(newMessage.length() > 0)
{
text.setText("");
addNewMessage(new Message(newMessage, false));
}
}
void addNewMessage(Message m)
{
messages.add(m);
adapter.notifyDataSetChanged();
getListView().setSelection(messages.size()-1);
}
}
AwesomeAdapter.java
public class AwesomeAdapter extends BaseAdapter{
private Context mContext;
private ArrayList<Message> mMessages;
public AwesomeAdapter(Context context, ArrayList<Message> messages) {
super();
this.mContext = context;
this.mMessages = messages;
}
@Override
public int getCount() {
return mMessages.size();
}
@Override
public Object getItem(int position) {
return mMessages.get(position);
}
@Override
public View getView(int position, View convertView, ViewGroup parent) {
Message message = (Message) this.getItem(position);
ViewHolder holder;
if(convertView == null)
{
holder = new ViewHolder();
convertView = LayoutInflater.from(mContext).inflate(R.layout.sms_row, parent, false);
holder.message = (TextView) convertView.findViewById(R.id.message_text);
convertView.setTag(holder);
}
else
holder = (ViewHolder) convertView.getTag();
holder.message.setText(message.getMessage());
LayoutParams lp = (LayoutParams) holder.message.getLayoutParams();
if(message.isMine())
{
holder.message.setBackgroundResource(R.drawable.me);
lp.setMargins(15, 10, 0, 10);
}
else
{
holder.message.setBackgroundResource(R.drawable.you);
lp.setMargins(0, 10, 15, 10);
}
holder.message.setLayoutParams(lp);
return convertView;
}
private static class ViewHolder
{
TextView message;
}
@Override
public long getItemId(int position) {
// TODO Auto-generated method stub
return 0;
}
}
消息.java
public class Message {
String message;
boolean isMine;
public Message(String message, boolean isMine) {
super();
this.message = message;
this.isMine = isMine;
}
/**
* Constructor to make a status Message object
* consider the parameters are swaped from default Message constructor,
* not a good approach but have to go with it.
*/
public Message(boolean status, String message) {
super();
this.message = message;
this.isMine = false;
}
public String getMessage() {
return message;
}
public boolean isMine() {
return isMine;
}
}
解决方案
收到新消息后,将该消息附加到前一条消息中 ArrayList<Message>
(IE。从数组列表中获取上一条消息并添加附加此新消息并换行(\n
)并且它应该可以工作)并调用 adapter.notifyDataSetChanged();
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